If three resistors, R1=50.0 kOhm, R2=50.0 kOhm and R3=25.0 kOhm, are placed in series, what resistor (Re) could be used to represent an equivalent resistance?

Hey there! Let’s figure out what happens when you connect three resistors in series—like plugging them in a straight line. Imagine resistors as little obstacles that slow down electricity in a circuit.

We’ve got three: R1 is 50.0 kOhm, R2 is 50.0 kOhm, and R3 is 25.0 kOhm. Our goal is to find one single resistor (called Re) that could replace all three and do the same job.

When resistors are in series, the electricity has to push through each one, one after the other. It’s like waiting in line at three different checkpoints—each one adds more time to your trip.

For resistors, each one adds more resistance to the flow of electricity. To find the total resistance, you just add them up. Super simple!

So, let’s do the math:

R1 = 50.0 kOhm (that’s 50,000 Ohms, since "k" means thousand)

R2 = 50.0 kOhm (another 50,000 Ohms)

R3 = 25.0 kOhm (25,000 Ohms)

Add them together:

50.0 + 50.0 + 25.0 = 125.0 kOhm.

That’s it! The equivalent resistance, Re, is 125.0 kOhm. This means you could swap out those three resistors for one 125.0 kOhm resistor, and the circuit would work the same way—like replacing three small speed bumps with one big one.

Why does this matter?

In electronics, knowing the total resistance helps you figure out how much current flows or how bright a light bulb might glow. For now, just remember: in series, resistances add up like stacking blocks. Easy peasy! So, Re = 125.0 kOhm is your answer. Cool, right?

Buy 22 KOhms Through Hole Resistor Online India 1% 1/4W AXIAL | Magnificette


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